• stebo@lemmy.dbzer0.com
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    23 hours ago

    By the way guys, a very similar approximation for 8, which also starts at 9.000 for n=1, but quickly gets much closer to 8 for increasing n, is:

    exp{-2(n-1)} + 8

    It approaches 8 about as fast as the above method but this one has a simple formula that is usable in python etc.